What is the solution for 9y^{''}-64y=0 ?

The solution for 9y^{''}-64y=0 is y=c_{1}e^{(8t)/3}+c_{2}e^{-(8t)/3}

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9y^{''}-64y=0

9 y^{^{''}} - 64 y = 0

y = c_{1} e^{\frac{8 t}{3}} + c_{2} e^{- \frac{8 t}{3}}

Solution steps

9 y^{''} (t) - 64 y = 0

Solve linear ODE:

y = c_{1} e^{\frac{8 t}{3}} + c_{2} e^{- \frac{8 t}{3}}

y = c_{1} e^{\frac{8 t}{3}} + c_{2} e^{- \frac{8 t}{3}}

y^{^{''}} - 25 y^{^{'}} + 144 y = 0, y (0) = 2, y^{^{'}} (0) = 5

4 y^{^{''}} - 4 y^{^{'}} + y = 0, y (0) = 0, y^{^{'}} (0) = 1

2 y^{^{''}} + 12 y^{^{'}} + 68 y = 0

y^{^{''}} + 14 y = 0

34 y + 10 y^{^{'}} + y^{^{''}} = 0, y (0) = - 3, y^{^{'}} (0) = 6

What is the solution for 9y^{''}-64y=0 ?
The solution for 9y^{''}-64y=0 is y=c_{1}e^{(8t)/3}+c_{2}e^{-(8t)/3}