What is (\partial)/(\partial y)(2y^3-3y^2-12y+6) ?

The answer to (\partial)/(\partial y)(2y^3-3y^2-12y+6) is 6y^2-6y-12

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(\partial)/(\partial y)(2y^3-3y^2-12y+6)

\frac{\partial}{\partial y} (2 y^{3} - 3 y^{2} - 12 y + 6)

6 y^{2} - 6 y - 12

Solution steps

\frac{\partial}{\partial y} (2 y^{3} - 3 y^{2} - 12 y + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 y^{3}) - \frac{\partial}{\partial y} (3 y^{2}) - \frac{\partial}{\partial y} (12 y) + \frac{\partial}{\partial y} (6)

\frac{\partial}{\partial y} (2 y^{3}) = 6 y^{2}

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

\frac{\partial}{\partial y} (12 y) = 12

\frac{\partial}{\partial y} (6) = 0

= 6 y^{2} - 6 y - 12 + 0

Simplify

= 6 y^{2} - 6 y - 12

(x^{2} + 1) y^{^{'}} + 8 x (y - 1) = 0, y (0) = 4

\int x e^{\frac{- x}{2}} d x

\int_{0}^{1} 8 ln (x) d x

\int (1 + e^{x}) d x

n = 1 \sum \infty \frac{8}{( n + 1 ) !}

What is (\partial)/(\partial y)(2y^3-3y^2-12y+6) ?
The answer to (\partial)/(\partial y)(2y^3-3y^2-12y+6) is 6y^2-6y-12