What is the integral from 0 to 1 of 8ln(x) ?

The integral from 0 to 1 of 8ln(x) is -8

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integral from 0 to 1 of 8ln(x)

\int_{0}^{1} 8 ln (x) d x

- 8

Solution steps

\int_{0}^{1} 8 ln (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{1} ln (x) d x

Apply Integration By Parts

: [x ln (x) - \int 1 d x]_{0}^{1}

= 8 [x ln (x) - \int 1 d x]_{0}^{1}

\int 1 d x = x

= 8 [x ln (x) - x]_{0}^{1}

Compute the boundaries:

- 1

= 8 (- 1)

Simplify

= - 8

\int (1 + e^{x}) d x

n = 1 \sum \infty \frac{8}{( n + 1 ) !}

\int (10 - x) d x

1 - \frac{x}{3}

\frac{∣ x - 2 ∣}{x ^{2}}

What is the integral from 0 to 1 of 8ln(x) ?
The integral from 0 to 1 of 8ln(x) is -8