What is maclaurin sqrt(1-x/3) ?

The answer to maclaurin sqrt(1-x/3) is 1-1/6 x-1/72 x^2-1/432 x^3-5/10368 x^4+\ldots

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maclaurin sqrt(1-x/3)

maclaurin

1 - \frac{x}{3}

1 - \frac{1}{6} x - \frac{1}{72} x^{2} - \frac{1}{432} x^{3} - \frac{5}{10368} x^{4} + \dots

Solution steps

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( 1 - \frac{x}{3} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 1 - \frac{x}{3} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 1 - \frac{x}{3} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{- \frac{1}{6}}{1 !} x + \frac{- \frac{1}{36}}{2 !} x^{2} + \frac{- \frac{1}{72}}{3 !} x^{3} + \frac{- \frac{5}{432}}{4 !} x^{4} + \dots

Refine

= 1 - \frac{1}{6} x - \frac{1}{72} x^{2} - \frac{1}{432} x^{3} - \frac{5}{10368} x^{4} + \dots

\frac{∣ x - 2 ∣}{x ^{2}}

\frac{d}{d x} (\frac{100}{( 1 + 5 x ) ^{3}})

\int \frac{1 + tan ( x )}{1 - tan ( x )} d x

x \to \infty lim ((1 - \frac{1}{4 x})^{8 x})

\int \frac{1}{x ^{2} e ^{\frac{1}{x}}} d x

What is maclaurin sqrt(1-x/3) ?
The answer to maclaurin sqrt(1-x/3) is 1-1/6 x-1/72 x^2-1/432 x^3-5/10368 x^4+\ldots