What is (\partial)/(\partial x)(x+y+xy) ?

The answer to (\partial)/(\partial x)(x+y+xy) is y+1

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(\partial)/(\partial x)(x+y+xy)

\frac{\partial}{\partial x} (x + y + x y)

y + 1

Solution steps

\frac{\partial}{\partial x} (x + y + x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (x y) = y

= 1 + 0 + y

Simplify

= y + 1

z \to 2 lim (7 z^{2} + 14 z - 7)

\int \frac{1}{( x ^{2} + 3 x - 4 )} d x

y = (3 x^{2} + 2) (4 x - 3)

\frac{5}{s - 3} - \frac{4}{s + 6}

\frac{d}{d x} (\frac{2 x + 1}{3 - x})

What is (\partial)/(\partial x)(x+y+xy) ?
The answer to (\partial)/(\partial x)(x+y+xy) is y+1