What is the integral of (x^3+2x-1) ?

The integral of (x^3+2x-1) is (x^4)/4+x^2-x+C

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integral of (x^3+2x-1)

\int (x^{3} + 2 x - 1) d x

\frac{x ^{4}}{4} + x^{2} - x + C

Solution steps

\int x^{3} + 2 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{3} d x + \int 2 x d x - \int 1 d x

\int x^{3} d x = \frac{x ^{4}}{4}

\int 2 x d x = x^{2}

\int 1 d x = x

= \frac{x ^{4}}{4} + x^{2} - x

Add a constant to the solution

= \frac{x ^{4}}{4} + x^{2} - x + C

a^{3} + cos^{3} (x)

y = ∣ 5 x ∣, y = x^{2} - 6

\frac{d}{d x} (ln (1 - 2 x))

\frac{\partial}{\partial θ} (- e^{- 3 r} sin (θ))

x \to \infty lim (10)

What is the integral of (x^3+2x-1) ?
The integral of (x^3+2x-1) is (x^4)/4+x^2-x+C