Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}-7y^'-8y=0,y(0)=5,y^'(0)=-5y^{'''''}-2y^{'''}-2y^{''}-3y^'-2y=0(d^2y)/(dt^2)-6(dy)/(dt)=0y^{'''}+7y^'=0x^{''}=bx
Frequently Asked Questions (FAQ)
What is the solution for 2y^{''}-2y=0 ?
The solution for 2y^{''}-2y=0 is y=c_{1}e^t+c_{2}e^{-t}