What is the derivative of f(x)=3x^2-4x ?

The derivative of f(x)=3x^2-4x is 6x-4

What is the first derivative of f(x)=3x^2-4x ?

The first derivative of f(x)=3x^2-4x is 6x-4

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derivative of

f (x) = 3 x^{2} - 4 x

6 x - 4

Solution steps

\frac{d}{d x} (3 x^{2} - 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

= 6 x - 4

y^{^{''}} + 2 y^{^{'}} + 26 y = 0, y (0) = 4, y^{^{'}} (0) = - 2

\frac{d}{d x} (x \cdot ln (x))

\frac{\partial}{\partial x} (x^{2 + y^{2}})

\int (15 x^{4}) d x

\frac{d}{d x} (\frac{- 7 x ^{2}}{2 x ^{2} - 5})

What is the derivative of f(x)=3x^2-4x ?
The derivative of f(x)=3x^2-4x is 6x-4
What is the first derivative of f(x)=3x^2-4x ?
The first derivative of f(x)=3x^2-4x is 6x-4