What is (\partial)/(\partial x)(x^{2+y^2}) ?

The answer to (\partial)/(\partial x)(x^{2+y^2}) is x^{y^2+1}(2+y^2)

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(\partial)/(\partial x)(x^{2+y^2})

\frac{\partial}{\partial x} (x^{2 + y^{2}})

x^{y^{2} + 1} (2 + y^{2})

Solution steps

\frac{\partial}{\partial x} (x^{2 + y^{2}})

Treat

y

as a constant

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (2 + y^{2}) x^{2 + y^{2} - 1}

Simplify

= x^{y^{2} + 1} (2 + y^{2})

\int (15 x^{4}) d x

\frac{d}{d x} (\frac{- 7 x ^{2}}{2 x ^{2} - 5})

\frac{d}{d x} (- cos (5 x))

\int 7 e^{4} d x

f (h) = x^{2} + 2 x + 7

What is (\partial)/(\partial x)(x^{2+y^2}) ?
The answer to (\partial)/(\partial x)(x^{2+y^2}) is x^{y^2+1}(2+y^2)