What is the derivative of f(h)=x^2+2x+7 ?

The derivative of f(h)=x^2+2x+7 is 2x+2

What is the first derivative of f(h)=x^2+2x+7 ?

The first derivative of f(h)=x^2+2x+7 is 2x+2

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derivative of

f (h) = x^{2} + 2 x + 7

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (7)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (7) = 0

= 2 x + 2 + 0

Simplify

= 2 x + 2

2 y^{^{''}} + 8 y^{^{'}} + 8 y = 0

5 x^{4} e^{x} + e^{x} x^{5}

\frac{d}{d x} (x^{4} - 2 x^{2} - 8)

\frac{d y}{d x}, y = 2^{x}

x \to 0 lim (\frac{2 x}{3 x})

What is the derivative of f(h)=x^2+2x+7 ?
The derivative of f(h)=x^2+2x+7 is 2x+2
What is the first derivative of f(h)=x^2+2x+7 ?
The first derivative of f(h)=x^2+2x+7 is 2x+2