What is the derivative of x^4-2x^2-8 ?

The derivative of x^4-2x^2-8 is 4x^3-4x

What is the first derivative of x^4-2x^2-8 ?

The first derivative of x^4-2x^2-8 is 4x^3-4x

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\frac{d}{d x} (x^{4} - 2 x^{2} - 8)

4 x^{3} - 4 x

Solution steps

\frac{d}{d x} (x^{4} - 2 x^{2} - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) - \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (8) = 0

= 4 x^{3} - 4 x - 0

Simplify

= 4 x^{3} - 4 x

\frac{d y}{d x}, y = 2^{x}

x \to 0 lim (\frac{2 x}{3 x})

\int_{0}^{1} 5^{x} d x

sin (6 x)

y = \frac{1}{( t ^{4} + 1 ) ^{3}}

What is the derivative of x^4-2x^2-8 ?
The derivative of x^4-2x^2-8 is 4x^3-4x
What is the first derivative of x^4-2x^2-8 ?
The first derivative of x^4-2x^2-8 is 4x^3-4x