What is the solution for (D^3-D^2-4D+4)y=0 ?

The solution for (D^3-D^2-4D+4)y=0 is y=c_{1}e^x+c_{2}e^{-2x}+c_{3}e^{2x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(D^3-D^2-4D+4)y=0

(D^{3} - D^{2} - 4 D + 4) y = 0

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

Solution steps

(D^{3} - D^{2} - 4 D + 4) y = 0

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

y = c_{1} e^{x} + c_{2} e^{- 2 x} + c_{3} e^{2 x}

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y^{0} = 0, y^{^{'}} 0 = 1

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (0) = - 4, y^{^{'}} (0) = - 8

4 y^{^{''}} + 16 y^{^{'}} + \frac{1}{16} y = 0

y^{^{''}} + 5 y^{^{'}} + 6 y = 0, y (0) = 10, y^{^{'}} (0) = 0

y^{^{''}} - 4 y = 0, y (0) = 6, y^{^{'}} (0) = 0

What is the solution for (D^3-D^2-4D+4)y=0 ?
The solution for (D^3-D^2-4D+4)y=0 is y=c_{1}e^x+c_{2}e^{-2x}+c_{3}e^{2x}