What is the derivative of sin(ln(4x)) ?

The derivative of sin(ln(4x)) is (cos(ln(4x)))/x

What is the first derivative of sin(ln(4x)) ?

The first derivative of sin(ln(4x)) is (cos(ln(4x)))/x

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\frac{d}{d x} (sin (ln (4 x)))

\frac{cos ( ln ( 4 x ) )}{x}

Solution steps

\frac{d}{d x} (sin (ln (4 x)))

Apply the chain rule:

cos (ln (4 x)) \frac{d}{d x} (ln (4 x))

= cos (ln (4 x)) \frac{d}{d x} (ln (4 x))

\frac{d}{d x} (ln (4 x)) = \frac{1}{x}

= cos (ln (4 x)) \frac{1}{x}

Simplify

cos (ln (4 x)) \frac{1}{x} : \frac{cos ( ln ( 4 x ) )}{x}

= \frac{cos ( ln ( 4 x ) )}{x}

e^{- 4 x^{2}}

x \to - 1 lim (16 - 4 x)

\int ((y) ln (1 + y)) d y

\int (2 + \frac{5}{7} x - 6 x^{2}) d x

\frac{d}{d x} ((x - 5) x - 5)

What is the derivative of sin(ln(4x)) ?
The derivative of sin(ln(4x)) is (cos(ln(4x)))/x
What is the first derivative of sin(ln(4x)) ?
The first derivative of sin(ln(4x)) is (cos(ln(4x)))/x