What is the derivative of 4x^3+3x^2-6x ?

The derivative of 4x^3+3x^2-6x is 12x^2+6x-6

What is the first derivative of 4x^3+3x^2-6x ?

The first derivative of 4x^3+3x^2-6x is 12x^2+6x-6

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\frac{d}{d x} (4 x^{3} + 3 x^{2} - 6 x)

12 x^{2} + 6 x - 6

Solution steps

\frac{d}{d x} (4 x^{3} + 3 x^{2} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

= 12 x^{2} + 6 x - 6

y - x \frac{d y}{d x} = a (1 + x^{2} \frac{d y}{d x})

f (x) = (5 x - 9) (x + 5), (2, 7)

x^{^{''}} + 10 x^{^{'}} + 21 x = 0

\int \frac{x + 10}{x ^{2} - x - 2} d x

\int_{- 3}^{0} (9 - x^{2}) d x

What is the derivative of 4x^3+3x^2-6x ?
The derivative of 4x^3+3x^2-6x is 12x^2+6x-6
What is the first derivative of 4x^3+3x^2-6x ?
The first derivative of 4x^3+3x^2-6x is 12x^2+6x-6