What is the solution for 9y^{''}-30y^'-24y=0,y(0)=1,y^'(0)=0 ?

The solution for 9y^{''}-30y^'-24y=0,y(0)=1,y^'(0)=0 is y=(1-6/7)e^{4t}+6/7 e^{-(2t)/3}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9y^{''}-30y^'-24y=0,y(0)=1,y^'(0)=0

9 y^{^{''}} - 30 y^{^{'}} - 24 y = 0, y (0) = 1, y^{^{'}} (0) = 0

y = (1 - \frac{6}{7}) e^{4 t} + \frac{6}{7} e^{- \frac{2 t}{3}}

Solution steps

9 y^{''} (t) - 30 y^{'} (t) - 24 y = 0

Solve linear ODE:

y = (1 - \frac{6}{7}) e^{4 t} + \frac{6}{7} e^{- \frac{2 t}{3}}

y = (1 - \frac{6}{7}) e^{4 t} + \frac{6}{7} e^{- \frac{2 t}{3}}

f^{^{''}} (x) = - \frac{f ^{^{'}} ( x )}{2 ( n + 2 )}

y^{^{''}} - y = 0, y (0) = 1

u^{^{''}} + 49 H (t) = 0, H (0) = 3, u^{^{'}} (0) = - 7

y^{^{'''}} - 6 y^{^{''}} + 11 y^{^{'}} - 6 y = 0, y (π) = 0

y^{^{''}} + y = 0, y^{^{''}} (0) = 0, y (0) = 1

What is the solution for 9y^{''}-30y^'-24y=0,y(0)=1,y^'(0)=0 ?
The solution for 9y^{''}-30y^'-24y=0,y(0)=1,y^'(0)=0 is y=(1-6/7)e^{4t}+6/7 e^{-(2t)/3}