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Popular >

2u^{''}+u^'+3\H(t)=0

Solution

2 u^{''} + u^{'} + 3 H (t (x)) = 0

Solution

2 \cdot 0 + 0 + 3 H (t (x)) = 0

Solution steps

2 u^{''} + u^{'} + 3 H (t (x)) = 0

u^{''} = 0

2 \cdot 0 + u^{^{'}} + 3 H (t (x)) = 0

u^{'} = 0

2 \cdot 0 + 0 + 3 H (t (x)) = 0

Popular Examples

y^{''}+2y^'-10y=0,y(0)=2,y^'(0)=-1

y^{^{''}} + 2 y^{^{'}} - 10 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

2y^{''}-0y^'+18y=0

2 y^{^{''}} - 0 y^{^{'}} + 18 y = 0

linear x^{''}+4x^'+4x=0 linear

x^{^{''}} + 4 x^{^{'}} + 4 x = 0

u^{''}+49\H(t)=0,\H(0)=3,u^'(0)=7

u^{^{''}} + 49 H (t) = 0, H (0) = 3, u^{^{'}} (0) = 7

24y^{''}+14y^'-3y=0

24 y^{^{''}} + 14 y^{^{'}} - 3 y = 0

Frequently Asked Questions (FAQ)

What is 2u^{''}+u^'+3\H(t)=0 ?
The answer to 2u^{''}+u^'+3\H(t)=0 is 2*0+0+3\H(t(x))=0