What is the derivative of (3-x/2) ?

The derivative of (3-x/2) is -1/2

What is the first derivative of (3-x/2) ?

The first derivative of (3-x/2) is -1/2

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\frac{d}{d x} (\frac{3 - x}{2})

- \frac{1}{2}

Solution steps

\frac{d}{d x} (\frac{3 - x}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (3 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d}{d x} (3) - \frac{d x}{d x})

\frac{d}{d x} (3) = 0

\frac{d x}{d x} = 1

= \frac{1}{2} (0 - 1)

Simplify

= - \frac{1}{2}

x^{4} cos (x)

\int 2 t \cdot e^{t} d t

y = x^{2} - 1.521, y = - x^{2} + 1.521

x \to 0 - lim (2^{\frac{1}{x}} + 2)

\frac{e ^{- s}}{s}

What is the derivative of (3-x/2) ?
The derivative of (3-x/2) is -1/2
What is the first derivative of (3-x/2) ?
The first derivative of (3-x/2) is -1/2