What is the limit as x approaches 0-of 2^{1/x}+2 ?

The limit as x approaches 0-of 2^{1/x}+2 is 2

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limit as x approaches 0-of 2^{1/x}+2

x \to 0 - lim (2^{\frac{1}{x}} + 2)

2

Solution steps

x \to 0 - lim (2^{\frac{1}{x}} + 2)

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (2^{\frac{1}{x}}) + x \to 0 - lim (2)

x \to 0 - lim (2^{\frac{1}{x}}) = 0

x \to 0 - lim (2) = 2

= 0 + 2

Simplify

= 2

\frac{e ^{- s}}{s}

(1 + e^{x}) y \frac{d y}{d x} = e^{y}

8 x \frac{d y}{d x} = 2 x e^{x} - 8 y + 6 x^{2}

\frac{sec ( 9 x )}{1 + sec ( 9 x )}

\frac{\partial}{\partial x} (\frac{- x - 9 y}{2 y - 7 x})

What is the limit as x approaches 0-of 2^{1/x}+2 ?
The limit as x approaches 0-of 2^{1/x}+2 is 2