What is the solution for 8x(dy)/(dx)=2xe^x-8y+6x^2 ?

The solution for 8x(dy)/(dx)=2xe^x-8y+6x^2 is y=(e^xx-e^x}{4x}+\frac{x^2)/4+(c_{1})/x

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8x(dy)/(dx)=2xe^x-8y+6x^2

8 x \frac{d y}{d x} = 2 x e^{x} - 8 y + 6 x^{2}

y = \frac{e ^{x} x - e ^{x}}{4 x} + \frac{x ^{2}}{4} + \frac{c _{1}}{x}

Solution steps

8 x \frac{d y}{d x} = 2 x e^{x} - 8 y + 6 x^{2}

Solve linear ODE:

y = \frac{e ^{x} x - e ^{x}}{4 x} + \frac{x ^{2}}{4} + \frac{c _{1}}{x}

y = \frac{e ^{x} x - e ^{x}}{4 x} + \frac{x ^{2}}{4} + \frac{c _{1}}{x}

\frac{sec ( 9 x )}{1 + sec ( 9 x )}

\frac{\partial}{\partial x} (\frac{- x - 9 y}{2 y - 7 x})

\frac{d}{d x} (3 sin (x) - 4 sin^{3} (x))

x \to 0 + lim (\frac{1}{1 - e ^{x}} - \frac{1}{x})

\frac{d}{d x} (\frac{1}{x ^{2}} + \frac{1}{x})

What is the solution for 8x(dy)/(dx)=2xe^x-8y+6x^2 ?
The solution for 8x(dy)/(dx)=2xe^x-8y+6x^2 is y=(e^xx-e^x}{4x}+\frac{x^2)/4+(c_{1})/x