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Popular >

5y^{''}+80y=0

Solution

5 y^{^{''}} + 80 y = 0

Solution

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Solution steps

5 y^{''} (t) + 80 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Popular Examples

y^{''}+7y^'+10y=0,y(0)=11,y^'(0)=-49

y^{^{''}} + 7 y^{^{'}} + 10 y = 0, y (0) = 11, y^{^{'}} (0) = - 49

4000y^{''}-9y^'=0

4000 y^{^{''}} - 9 y^{^{'}} = 0

y^{''}+by^'+6y=0,y(0)=1,y^'(0)=0

y^{^{''}} + b y^{^{'}} + 6 y = 0, y (0) = 1, y^{^{'}} (0) = 0

x^{^{''}} + 64 x^{^{'}} = 0

3(d^2y)/(dx^2)-14(dy)/(dx)-5y=0

3 \frac{d ^{2} y}{d x ^{2}} - 14 \frac{d y}{d x} - 5 y = 0

Frequently Asked Questions (FAQ)

What is the solution for 5y^{''}+80y=0 ?
The solution for 5y^{''}+80y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)