What is the solution for y^{''}+1960y=0,y(0)=0.015,y^'(0)=0 ?

The solution for y^{''}+1960y=0,y(0)=0.015,y^'(0)=0 is y=0.015cos(14sqrt(10)t)

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y^{''}+1960y=0,y(0)=0.015,y^'(0)=0

y^{^{''}} + 1960 y = 0, y (0) = 0.015, y^{^{'}} (0) = 0

y = 0.015 cos (1410 t)

Solution steps

y^{''} (t) + 1960 y = 0

Solve linear ODE:

y = 0.015 cos (1410 t)

y = 0.015 cos (1410 t)

y^{^{''}} - 4 y + 7 y = 0

y^{^{''}} + 100 y = 0, y (π) = 5, y (0) = 2

y^{^{'''}} + 9 y^{^{'}} = 0, y (0) = 7

2 y^{^{''}} - 13 y^{^{'}} + 15 y = 0, y (0) = 0, y^{^{'}} (0) = 17.5

θ^{^{''}} (t) + \frac{9. 8 ^{2}}{80} θ (t) = 0

What is the solution for y^{''}+1960y=0,y(0)=0.015,y^'(0)=0 ?
The solution for y^{''}+1960y=0,y(0)=0.015,y^'(0)=0 is y=0.015cos(14sqrt(10)t)