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Popular >

xy^'+y=0

Solution

x y^{^{'}} + y = 0

Solution

y = \frac{c _{1}}{x}

Solution steps

x y^{'} (x) + y = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

Popular Examples

(d^2)/(dx^2)(\sqrt[5]{x})

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arccos (x) + x

integral of 1/((3sin(x)-4cos(x)))

\int \frac{1}{( 3 sin ( x ) - 4 cos ( x ) )} d x

d/(dn)(ln(n+1))

\frac{d}{d n} (ln (n + 1))

integral of 6/((x-4)^3)

\int \frac{6}{( x - 4 ) ^{3}} d x

Frequently Asked Questions (FAQ)

What is the solution for xy^'+y=0 ?
The solution for xy^'+y=0 is y=(c_{1})/x