What is the solution for y(dy)/(dx)=xe^{-y^2} ?

The solution for y(dy)/(dx)=xe^{-y^2} is y=sqrt(ln(x^2+c_{1))},y=-sqrt(ln(x^2+c_{1))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y(dy)/(dx)=xe^{-y^2}

y \frac{d y}{d x} = x e^{- y^{2}}

y = ln (x^{2} + c_{1}), y = - ln (x^{2} + c_{1})

Solution steps

y \frac{d y}{d x} = x e^{- y^{2}}

Solve separable ODE:

y = ln (x^{2} + c_{1}), y = - ln (x^{2} + c_{1})

y = ln (x^{2} + c_{1}), y = - ln (x^{2} + c_{1})

\frac{5 x}{x - 2}

\int \frac{( x ^{2} - x + 12 )}{x ^{3} + 2 x} d x

\int_{0}^{\infty} e^{- u} d u

\frac{d y}{d x} = y^{2} - 3 y

t \to 0 lim (\frac{( 3 e ^{t} - 3 )}{t})

What is the solution for y(dy)/(dx)=xe^{-y^2} ?
The solution for y(dy)/(dx)=xe^{-y^2} is y=sqrt(ln(x^2+c_{1))},y=-sqrt(ln(x^2+c_{1))}