What is the integral of ((x^2-x+12))/(x^3+2x) ?

The integral of ((x^2-x+12))/(x^3+2x) is 6ln|x|-5/2 ln|x^2+2|-1/(sqrt(2))arctan(x/(sqrt(2)))+C

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integral of ((x^2-x+12))/(x^3+2x)

\int \frac{( x ^{2} - x + 12 )}{x ^{3} + 2 x} d x

6 ln ∣ x ∣ - \frac{5}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2}) + C

Solution steps

\int \frac{x ^{2} - x + 12}{x ^{3} + 2 x} d x

Take the partial fraction of

\frac{x ^{2} - x + 12}{x ^{3} + 2 x} : \frac{6}{x} + \frac{- 5 x - 1}{x ^{2} + 2}

= \int \frac{6}{x} + \frac{- 5 x - 1}{x ^{2} + 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6}{x} d x + \int \frac{- 5 x - 1}{x ^{2} + 2} d x

\int \frac{6}{x} d x = 6 ln ∣ x ∣

\int \frac{- 5 x - 1}{x ^{2} + 2} d x = - \frac{5}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2})

= 6 ln ∣ x ∣ - \frac{5}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2})

Add a constant to the solution

= 6 ln ∣ x ∣ - \frac{5}{2} ln x^{2} + 2 - \frac{1}{2} arctan (\frac{x}{2}) + C

\int_{0}^{\infty} e^{- u} d u

\frac{d y}{d x} = y^{2} - 3 y

t \to 0 lim (\frac{( 3 e ^{t} - 3 )}{t})

\frac{d}{d x} (- \frac{2 x}{( x ^{2} + 3 ) ^{2}})

x \to 0 + lim (\frac{8 x}{sin ( x )})

What is the integral of ((x^2-x+12))/(x^3+2x) ?
The integral of ((x^2-x+12))/(x^3+2x) is 6ln|x|-5/2 ln|x^2+2|-1/(sqrt(2))arctan(x/(sqrt(2)))+C