What is the solution for linear y^{''}+(216/7)y=0 ?

The solution for linear y^{''}+(216/7)y=0 is y=c_{1}cos(sqrt((6^3)/7)t)+c_{2}sin(sqrt((6^3)/7)t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

linear y^{''}+(216/7)y=0

linear

y^{^{''}} + (\frac{216}{7}) y = 0

y = c_{1} cos (\frac{6 ^{3}}{7} t) + c_{2} sin (\frac{6 ^{3}}{7} t)

Solution steps

y^{''} (t) + (\frac{216}{7}) y = 0

Solve linear ODE:

y = c_{1} cos (\frac{6 ^{3}}{7} t) + c_{2} sin (\frac{6 ^{3}}{7} t)

y = c_{1} cos (\frac{6 ^{3}}{7} t) + c_{2} sin (\frac{6 ^{3}}{7} t)

(D^{5} - 5 D^{4} + 7 D^{3} + D^{2} - 8 D + 4) y = 0

y^{^{''}} - 7 y + 12 y = 0

(y^{^{''}} + 2 y^{^{'}} + 5 y) = 0

y^{^{''}} - 2 y^{^{'}} + 5 y = 0, y (0) = 2, y^{^{'}} (0) = - 2

y^{^{''}} + y^{^{'}} - 6 y = 0, y (0) = α, y^{^{'}} (0) = 5

What is the solution for linear y^{''}+(216/7)y=0 ?
The solution for linear y^{''}+(216/7)y=0 is y=c_{1}cos(sqrt((6^3)/7)t)+c_{2}sin(sqrt((6^3)/7)t)