What is the limit as z approaches 1+i of z^2+i ?

The limit as z approaches 1+i of z^2+i is 3i

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limit as z approaches 1+i of z^2+i

z \to 1 + i lim (z^{2} + i)

3 i

Solution steps

z \to 1 + i lim (z^{2} + i)

Plug in the value

z = 1 + i

= (1 + i)^{2} + i

Simplify

(1 + i)^{2} + i : 3 i

= 3 i

\int (3 x - 5)^{4} d x

\int \frac{1 + x}{x ^{2}} d x

f (x) = - x^{2} + 3 x + 2

f (x) = 5 x^{2} + 3 x + 8

\frac{7}{8 x ^{3}}

What is the limit as z approaches 1+i of z^2+i ?
The limit as z approaches 1+i of z^2+i is 3i