What is the derivative of 7/(8x^3) ?

The derivative of 7/(8x^3) is -(21)/(8x^4)

What is the first derivative of 7/(8x^3) ?

The first derivative of 7/(8x^3) is -(21)/(8x^4)

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derivative of

\frac{7}{8 x ^{3}}

- \frac{21}{8 x ^{4}}

Solution steps

\frac{d}{d x} (\frac{7}{8 x ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{7}{8} \frac{d}{d x} (\frac{1}{x ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{7}{8} \frac{d}{d x} (x^{- 3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{7}{8} (- 3 x^{- 3 - 1})

Simplify

\frac{7}{8} (- 3 x^{- 3 - 1}) : - \frac{21}{8 x ^{4}}

= - \frac{21}{8 x ^{4}}

\frac{d}{d x} (e^{- \frac{x}{5}})

f (x) = \frac{1}{( 1 + x ^{2} )}, at x = 1

\frac{d y}{d x} + y = \frac{1 - e ^{- 2 x}}{e ^{x} - e ^{- x}}

\int x (4 x - 3)^{10} d x

\frac{d}{d x} ((3 x^{2} - 2 x + 3)^{5})

What is the derivative of 7/(8x^3) ?
The derivative of 7/(8x^3) is -(21)/(8x^4)
What is the first derivative of 7/(8x^3) ?
The first derivative of 7/(8x^3) is -(21)/(8x^4)