What is (\partial)/(\partial x)(1/(x^2y^2)) ?

The answer to (\partial)/(\partial x)(1/(x^2y^2)) is -2/(x^3y^2)

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(\partial)/(\partial x)(1/(x^2y^2))

\frac{\partial}{\partial x} (\frac{1}{x ^{2} y ^{2}})

- \frac{2}{x ^{3} y ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{1}{x ^{2} y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{y ^{2}} \frac{\partial}{\partial x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{y ^{2}} \frac{\partial}{\partial x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{y ^{2}} (- 2 x^{- 2 - 1})

Simplify

\frac{1}{y ^{2}} (- 2 x^{- 2 - 1}) : - \frac{2}{x ^{3} y ^{2}}

= - \frac{2}{x ^{3} y ^{2}}

\int t 2^{t^{2}} d t

\frac{d y}{d t} + y = e^{- t}

\frac{\partial}{\partial x} (\frac{1}{( 1 - x )})

\int \frac{x ^{2} + 9 x + 1}{( x ^{2} + 1 ) ^{2}} d x

\frac{d}{d x} ((2 x + 1) (3 x - 2))

What is (\partial)/(\partial x)(1/(x^2y^2)) ?
The answer to (\partial)/(\partial x)(1/(x^2y^2)) is -2/(x^3y^2)