What is the solution for y^{''}+100/1 y^'=0 ?

The solution for y^{''}+100/1 y^'=0 is y=c_{1}+c_{2}e^{-100t}

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y^{''}+100/1 y^'=0

y^{^{''}} + \frac{100}{1} y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 100 t}

Solution steps

y^{''} (t) + \frac{100}{1} y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 100 t}

y = c_{1} + c_{2} e^{- 100 t}

y^{^{''}} + 3 y^{^{'}} + (1 + a) y = 0

y^{^{''}} = 2 y + y^{^{'}}

y^{^{''''}} - y^{^{''}} = 0

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 23, y (1) = 0

y^{^{'''}} - 2 y^{^{'}} = 0

What is the solution for y^{''}+100/1 y^'=0 ?
The solution for y^{''}+100/1 y^'=0 is y=c_{1}+c_{2}e^{-100t}