What is the solution for -derivative of y= 4/x ?

The solution for -derivative of y= 4/x is y=-4ln(x)+c_{1}

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Find the Derivative - d/dx y=4/x

- \frac{d}{d x} y = \frac{4}{x}

y = - 4 ln (x) + c_{1}

Solution steps

- \frac{d y}{d x} = \frac{4}{x}

Isolate

y^{'} (x) : y^{'} (x) = - \frac{4}{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - \frac{4}{x} d x

\int - \frac{4}{x} d x = - 4 ln (x) + c_{1}

y = - 4 ln (x) + c_{1}

- \frac{d}{d x} (\frac{1}{x})

- \frac{d}{d x} y = 3 x

(2, 5), (3, 6)

f = 4 x + 3

cos (θ)

What is the solution for -derivative of y= 4/x ?
The solution for -derivative of y= 4/x is y=-4ln(x)+c_{1}