What is the solution for (dy}{dx}y=\frac{x+1)/x ?

The solution for (dy}{dx}y=\frac{x+1)/x is y=sqrt(2x+2ln(x)+c_{1)},y=-sqrt(2x+2ln(x)+c_{1)}

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Find dy/dx y=x+1/x

\frac{d y}{d x} y = \frac{x + 1}{x}

y = 2 x + 2 ln (x) + c_{1}, y = - 2 x + 2 ln (x) + c_{1}

Solution steps

\frac{d y}{d x} y = \frac{x + 1}{x}

Solve separable ODE:

y = 2 x + 2 ln (x) + c_{1}, y = - 2 x + 2 ln (x) + c_{1}

y = 2 x + 2 ln (x) + c_{1}, y = - 2 x + 2 ln (x) + c_{1}

\int (e^{2 x} x^{2}) d x

n = 1 \sum \infty (\frac{- 1}{3})^{n - 1}

x \to 0 lim (\frac{( sin ( cos ( x ) ) )}{( sec ( x ) )})

- \frac{d}{d t} (sin (2 t))

- \frac{d}{d x} y = 3 e^{x}

What is the solution for (dy}{dx}y=\frac{x+1)/x ?
The solution for (dy}{dx}y=\frac{x+1)/x is y=sqrt(2x+2ln(x)+c_{1)},y=-sqrt(2x+2ln(x)+c_{1)}