What is the solution for -derivative of y=3e^x ?

The solution for -derivative of y=3e^x is y=-3e^x+c_{1}

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Find the Derivative - d/dx y=3e^x

- \frac{d}{d x} y = 3 e^{x}

y = - 3 e^{x} + c_{1}

Solution steps

- \frac{d y}{d x} = 3 e^{x}

Isolate

y^{'} (x) : y^{'} (x) = - 3 e^{x}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int - 3 e^{x} d x

\int - 3 e^{x} d x = - 3 e^{x} + c_{1}

y = - 3 e^{x} + c_{1}

- \frac{d}{d t} (2 t)

- \frac{d}{d x} f (x) = e^{6 x}

f (x) = sin (2 x)

f (x) = \frac{1}{( x ^{3} )}

- \frac{d}{d x} (a^{x})

What is the solution for -derivative of y=3e^x ?
The solution for -derivative of y=3e^x is y=-3e^x+c_{1}