What is the integral of f(x)= 1/((x^3)) ?

The integral of f(x)= 1/((x^3)) is -1/(2x^2)+C

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Find the Antiderivative f(x)=1/(x^3)

integral

f (x) = \frac{1}{( x ^{3} )}

- \frac{1}{2 x ^{2}} + C

Solution steps

\int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

Add a constant to the solution

= - \frac{1}{2 x ^{2}} + C

\frac{d}{d x} (e^{\frac{1}{x}})

\frac{d}{d x} (a^{x})

1 x

\frac{1}{( tan ( x ) )}

\frac{d}{d x} y = 8 x

What is the integral of f(x)= 1/((x^3)) ?
The integral of f(x)= 1/((x^3)) is -1/(2x^2)+C