What is the integral from 0 to 2 of x^3-3x^2+2x ?

The integral from 0 to 2 of x^3-3x^2+2x is 0

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integral from 0 to 2 of x^3-3x^2+2x

\int_{0}^{2} x^{3} - 3 x^{2} + 2 x d x

0

Solution steps

\int_{0}^{2} x^{3} - 3 x^{2} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{3} d x - \int_{0}^{2} 3 x^{2} d x + \int_{0}^{2} 2 x d x

\int_{0}^{2} x^{3} d x = 4

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} 2 x d x = 4

= 4 - 8 + 4

Simplify

= 0

x^{2} - 5 x + 5

\int x^{3} x^{2} + 8 d x

\frac{d}{d x} (\frac{1}{arctan ( x ^{2} )})

\int cos^{2} (x) d x

(1 + cos (t)) \frac{d y}{d t} = (1 + e^{- y}) sin (t)

What is the integral from 0 to 2 of x^3-3x^2+2x ?
The integral from 0 to 2 of x^3-3x^2+2x is 0