What is the solution for (1+cos(t))(dy)/(dt)=(1+e^{-y})sin(t) ?

The solution for (1+cos(t))(dy)/(dt)=(1+e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))-1)

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(1+cos(t))(dy)/(dt)=(1+e^{-y})sin(t)

(1 + cos (t)) \frac{d y}{d t} = (1 + e^{- y}) sin (t)

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

Solution steps

(1 + cos (t)) \frac{d y}{d t} = (1 + e^{- y}) sin (t)

Solve separable ODE:

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

y = ln (\frac{c _{1}}{1 + cos ( t )} - 1)

\frac{d}{d x} ((\frac{2 x + 1}{3 x - 1})^{4})

\frac{d}{d x} (8 x^{2} cos (x) cot (x))

x \cdot e^{- x + 1}

(4, - 4), (8, - 10)

\int \frac{3 + x}{3 - x} d x

What is the solution for (1+cos(t))(dy)/(dt)=(1+e^{-y})sin(t) ?
The solution for (1+cos(t))(dy)/(dt)=(1+e^{-y})sin(t) is y=ln((c_{1})/(1+cos(t))-1)