What is the derivative of 4t^3 ?

The derivative of 4t^3 is 12t^2

What is the first derivative of 4t^3 ?

The first derivative of 4t^3 is 12t^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

4 t^{3}

12 t^{2}

Solution steps

\frac{d}{d t} (4 t^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d t} (t^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 \cdot 3 t^{3 - 1}

Simplify

= 12 t^{2}

x \to \infty + lim (4 x)

[x + (x + sin^{2} (x))^{3}]^{6}

\int x e^{y x} d x

\int \frac{ln ( x )}{x ( 1 - ln ^{2} ( x ) )} d x

\int_{- 1}^{5} ∣ x - 2 ∣ d x