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Popular >

integral from-1 to 5 of |x-2|

Solution

\int_{- 1}^{5} ∣ x - 2 ∣ d x

Solution

9

Solution steps

\int_{- 1}^{5} ∣ x - 2 ∣ d x

Eliminate Absolutes

= \int_{- 1}^{2} - x + 2 d x + \int_{2}^{5} x - 2 d x

\int_{- 1}^{2} - x + 2 d x = \frac{9}{2}

\int_{2}^{5} x - 2 d x = \frac{9}{2}

= \frac{9}{2} + \frac{9}{2}

Simplify

\frac{9}{2} + \frac{9}{2} : 9

= 9

Popular Examples

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\int (2 + x^{5})^{8} x^{4} d x

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\frac{d}{d s} (\frac{s}{s ^{2} + w ^{2}})

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\frac{d}{d x} (- 8 e^{- 3 x})

Frequently Asked Questions (FAQ)

What is the integral from-1 to 5 of |x-2| ?
The integral from-1 to 5 of |x-2| is 9