What is the derivative of-8e^{-3x} ?

The derivative of-8e^{-3x} is 24e^{-3x}

What is the first derivative of-8e^{-3x} ?

The first derivative of-8e^{-3x} is 24e^{-3x}

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\frac{d}{d x} (- 8 e^{- 3 x})

24 e^{- 3 x}

Solution steps

\frac{d}{d x} (- 8 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 8 \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= - 8 e^{- 3 x} (- 3)

Simplify

= 24 e^{- 3 x}

\frac{d}{d x} (- 18 cos (3 x))

\int \frac{sin ^{5} ( θ )}{cos ( θ )} d θ

f (x) = (3 x^{3} + 3 x) (x - 3) (x + 5)

e^{x} x^{4} + 8 e^{x} x^{3} + 12 e^{x} x^{2}

\frac{d y}{d x} = 1 - y + x^{2} - y x^{2}

What is the derivative of-8e^{-3x} ?
The derivative of-8e^{-3x} is 24e^{-3x}
What is the first derivative of-8e^{-3x} ?
The first derivative of-8e^{-3x} is 24e^{-3x}