What is the solution for (dy)/(dx)=-(sqrt(x))/(4y) ?

The solution for (dy)/(dx)=-(sqrt(x))/(4y) is y=sqrt(-1/3 x^{3/2)+c_{1}},y=-sqrt(-1/3 x^{3/2)+c_{1}}

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(dy)/(dx)=-(sqrt(x))/(4y)

\frac{d y}{d x} = - \frac{x}{4 y}

y = - \frac{1}{3} x^{\frac{3}{2}} + c_{1}, y = - - \frac{1}{3} x^{\frac{3}{2}} + c_{1}

Solution steps

\frac{d y}{d x} = - \frac{x}{4 y}

Solve separable ODE:

y = - \frac{1}{3} x^{\frac{3}{2}} + c_{1}, y = - - \frac{1}{3} x^{\frac{3}{2}} + c_{1}

y = - \frac{1}{3} x^{\frac{3}{2}} + c_{1}, y = - - \frac{1}{3} x^{\frac{3}{2}} + c_{1}

\frac{\partial}{\partial y} (8 x y^{2} z^{3})

\int_{0}^{2} sin (x) d x

\int \frac{- 5 x + 2}{( x + 1 ) ^{2}} d x

\frac{d}{d x} (cos (x - \frac{π}{6}))

y^{^{'}} = y e^{x}

What is the solution for (dy)/(dx)=-(sqrt(x))/(4y) ?
The solution for (dy)/(dx)=-(sqrt(x))/(4y) is y=sqrt(-1/3 x^{3/2)+c_{1}},y=-sqrt(-1/3 x^{3/2)+c_{1}}