What is the limit as x approaches+0+of (x^2)/6-5/x ?

The limit as x approaches+0+of (x^2)/6-5/x is -infinity

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limit as x approaches+0+of (x^2)/6-5/x

x \to + 0 + lim (\frac{x ^{2}}{6} - \frac{5}{x})

- \infty

Solution steps

x \to 0 + lim (\frac{x ^{2}}{6} - \frac{5}{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 + lim (\frac{x ^{2}}{6}) - x \to 0 + lim (\frac{5}{x})

x \to 0 + lim (\frac{x ^{2}}{6}) = 0

x \to 0 + lim (\frac{5}{x}) = \infty

= 0 - \infty

Apply Infinity Property:

c - \infty = - \infty

= - \infty

\frac{d}{d x} ((x^{3} + 6) e^{x})

\frac{d}{d x} (sinh (0))

f (x) = x^{2}, at x = 3, x = 7

\int_{1}^{5} \frac{4}{x ^{2} + 4 x + 4} d x

\frac{d v}{d t} = \frac{1}{t ^{2}}

What is the limit as x approaches+0+of (x^2)/6-5/x ?
The limit as x approaches+0+of (x^2)/6-5/x is -infinity