What is the solution for (dy)/(dx)=(x-3)/(y-4) ?

The solution for (dy)/(dx)=(x-3)/(y-4) is y=4+sqrt(x^2-6x+c_{1)+16},y=4-sqrt(x^2-6x+c_{1)+16}

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(dy)/(dx)=(x-3)/(y-4)

\frac{d y}{d x} = \frac{x - 3}{y - 4}

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

Solution steps

\frac{d y}{d x} = \frac{x - 3}{y - 4}

Solve separable ODE:

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

y = 4 + x^{2} - 6 x + c_{1} + 16, y = 4 - x^{2} - 6 x + c_{1} + 16

\frac{\partial}{\partial x} ((2 x^{3} - 4 y) (2 x^{2} - 4))

\frac{d}{d x} (cos (\frac{π}{2}))

\int \frac{1}{x ^{2} - 2 x + 8} d x

\int \frac{1}{3 x} d x

\int (tan (x))^{3} (sec (x))^{2} d x

What is the solution for (dy)/(dx)=(x-3)/(y-4) ?
The solution for (dy)/(dx)=(x-3)/(y-4) is y=4+sqrt(x^2-6x+c_{1)+16},y=4-sqrt(x^2-6x+c_{1)+16}