What is the derivative of 18cos(x)+9sin^2(x) ?

The derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)

What is the first derivative of 18cos(x)+9sin^2(x) ?

The first derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)

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derivative of

18 cos (x) + 9 sin^{2} (x)

- 18 sin (x) + 9 sin (2 x)

Solution steps

\frac{d}{d x} (18 cos (x) + 9 sin^{2} (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (18 cos (x)) + \frac{d}{d x} (9 sin^{2} (x))

\frac{d}{d x} (18 cos (x)) = - 18 sin (x)

\frac{d}{d x} (9 sin^{2} (x)) = 9 sin (2 x)

= - 18 sin (x) + 9 sin (2 x)

\int - cos (u) d u

\frac{\partial}{\partial x} (ln (5 x^{2} + y^{2} + 9))

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = 0

f (x) = \frac{22}{( 1 - x ) ^{3}}

y = x^{2} - 2 x, (3, 3)

What is the derivative of 18cos(x)+9sin^2(x) ?
The derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)
What is the first derivative of 18cos(x)+9sin^2(x) ?
The first derivative of 18cos(x)+9sin^2(x) is -18sin(x)+9sin(2x)