What is the derivative of 8sin((2pi/3)) ?

The derivative of 8sin((2pi/3)) is 0

What is the first derivative of 8sin((2pi/3)) ?

The first derivative of 8sin((2pi/3)) is 0

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\frac{d}{d x} (8 sin (\frac{2 π}{3}))

0

Solution steps

\frac{d}{d x} (8 sin (\frac{2 π}{3}))

8 sin (\frac{2 π}{3}) = 43

= \frac{d}{d x} (43)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int \frac{2 x}{3 x - 5} d x

n = 1 \sum \infty \frac{n + 2}{n + 1}

\int ((1 - cos^{3} (x)) sin (x)) d x

\int (sin^{9} (x)) cos (x) d x

x \to 0 lim (\frac{sin ( 6 x )}{x})

What is the derivative of 8sin((2pi/3)) ?
The derivative of 8sin((2pi/3)) is 0
What is the first derivative of 8sin((2pi/3)) ?
The first derivative of 8sin((2pi/3)) is 0