What is the tangent of f(x)=5x^2-2x+4 ?

The tangent of f(x)=5x^2-2x+4 is y=(10a_{0}-2)x-5a_{0}^2+4

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tangent of f(x)=5x^2-2x+4

tangent of

f (x) = 5 x^{2} - 2 x + 4

y = (10 a_{0} - 2) x - 5 a_{0}^{2} + 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 5 a_{0}^{2} - 2 a_{0} + 4)

Find the slope of

f (x) = 5 x^{2} - 2 x + 4 : \frac{df ( x )}{d x} = 10 x - 2

Compute the slope of

f (x) = 5 x^{2} - 2 x + 4

x = a_{0} : m = 10 a_{0} - 2

Find the line with slope m=

10 a_{0} - 2

and passing through

(a_{0}, 5 a_{0}^{2} - 2 a_{0} + 4) : y = (10 a_{0} - 2) x - 5 a_{0}^{2} + 4

y = (10 a_{0} - 2) x - 5 a_{0}^{2} + 4

x \to - 4 + lim (\frac{- 1}{x ^{2} - 16})

x \to 1 lim (\frac{2 x - 7}{4 x + 5})

\frac{2}{s - 2}

\int \frac{- x ^{2} + 2 x - 8}{( x ^{2} + 4 ) ( x - 2 )} d x

\int x^{2} 4 x + 7 d x

What is the tangent of f(x)=5x^2-2x+4 ?
The tangent of f(x)=5x^2-2x+4 is y=(10a_{0}-2)x-5a_{0}^2+4