What is the tangent of f(x)=3-2cos(x),\at x= pi/2 ?

The tangent of f(x)=3-2cos(x),\at x= pi/2 is y=2x+3-pi

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tangent of f(x)=3-2cos(x),\at x= pi/2

tangent of

f (x) = 3 - 2 cos (x), at x = \frac{π}{2}

y = 2 x + 3 - π

Solution steps

Find the tangent point:

(\frac{π}{2}, 3)

Find the slope of

f (x) = 3 - 2 cos (x) : \frac{df ( x )}{d x} = 2 sin (x)

Compute the slope of

f (x) = 3 - 2 cos (x)

x = \frac{π}{2} : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{2}, 3) : y = 2 x + 3 - π

y = 2 x + 3 - π

\int \frac{2}{x ^{2} + 1} d x

f (x) = \frac{x + 5}{x + 2}

\int \frac{1}{x \cdot x ^{2} - 1} d x

\frac{\partial}{\partial x} (y^{4})

\frac{d}{d x} (\frac{4 x}{x + 3})

What is the tangent of f(x)=3-2cos(x),\at x= pi/2 ?
The tangent of f(x)=3-2cos(x),\at x= pi/2 is y=2x+3-pi