What is the integral of (6sin(2x)+sec^2(x)) ?

The integral of (6sin(2x)+sec^2(x)) is -3cos(2x)+tan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (6sin(2x)+sec^2(x))

\int (6 sin (2 x) + sec^{2} (x)) d x

- 3 cos (2 x) + tan (x) + C

Solution steps

\int 6 sin (2 x) + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 6 sin (2 x) d x + \int sec^{2} (x) d x

\int 6 sin (2 x) d x = - 3 cos (2 x)

\int sec^{2} (x) d x = tan (x)

= - 3 cos (2 x) + tan (x)

Add a constant to the solution

= - 3 cos (2 x) + tan (x) + C

\frac{d ^{2}}{d x ^{2}} (\frac{x ^{2}}{4 + x})

\int (125 x^{9}) d x

\frac{d}{d x} (2 cos (x^{2}) sin (2 x))

\frac{1}{s}

\frac{5 s + 5}{s ^{3} + 6 s ^{2} + 10 s}

What is the integral of (6sin(2x)+sec^2(x)) ?
The integral of (6sin(2x)+sec^2(x)) is -3cos(2x)+tan(x)+C