What is the integral of (125x^9) ?

The integral of (125x^9) is (25x^{10})/2+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (125x^9)

\int (125 x^{9}) d x

\frac{25 x ^{10}}{2} + C

Solution steps

\int 125 x^{9} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 125 \cdot \int x^{9} d x

Apply the Power Rule

: \frac{x ^{10}}{10}

= 125 \cdot \frac{x ^{10}}{10}

Simplify

125 \cdot \frac{x ^{10}}{10} : \frac{25 x ^{10}}{2}

= \frac{25 x ^{10}}{2}

Add a constant to the solution

= \frac{25 x ^{10}}{2} + C

\frac{d}{d x} (2 cos (x^{2}) sin (2 x))

\frac{1}{s}

\frac{5 s + 5}{s ^{3} + 6 s ^{2} + 10 s}

\frac{\partial}{\partial x} (x^{2} - 6 x y + y)

(- 4, - 3), (4, 2)