What is the integral from 1 to 3 of (9^x-7^x) ?

The integral from 1 to 3 of (9^x-7^x) is (360)/(ln(3))-(336)/(ln(7))

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integral from 1 to 3 of (9^x-7^x)

\int_{1}^{3} (9^{x} - 7^{x}) d x

\frac{360}{ln ( 3 )} - \frac{336}{ln ( 7 )}

Decimal Notation

155.01627 \dots

Solution steps

\int_{1}^{3} 9^{x} - 7^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 9^{x} d x - \int_{1}^{3} 7^{x} d x

\int_{1}^{3} 9^{x} d x = \frac{360}{ln ( 3 )}

\int_{1}^{3} 7^{x} d x = \frac{336}{ln ( 7 )}

= \frac{360}{ln ( 3 )} - \frac{336}{ln ( 7 )}

\frac{d}{d x} (\frac{x ^{2} - 2}{x ^{2} + 2})

y^{^{'}} = 7 y

\frac{d}{d x} ((2 x + 1)^{5} + 10 x (2 x + 1)^{4})

\frac{\partial}{\partial s} (2 s^{2} + t^{2})

\frac{\partial}{\partial s} (e^{s^{3} + t^{2}})

What is the integral from 1 to 3 of (9^x-7^x) ?
The integral from 1 to 3 of (9^x-7^x) is (360)/(ln(3))-(336)/(ln(7))