What is the derivative of (2x-3/((x^2+4)^2)) ?

The derivative of (2x-3/((x^2+4)^2)) is (2(-3x^2+6x+4))/((x^2+4)^3)

What is the first derivative of (2x-3/((x^2+4)^2)) ?

The first derivative of (2x-3/((x^2+4)^2)) is (2(-3x^2+6x+4))/((x^2+4)^3)

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\frac{d}{d x} (\frac{2 x - 3}{( x ^{2} + 4 ) ^{2}})

\frac{2 ( - 3 x ^{2} + 6 x + 4 )}{( x ^{2} + 4 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{2 x - 3}{( x ^{2} + 4 ) ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 x - 3 ) ( x ^{2} + 4 ) ^{2} - \frac{d}{d x} ( ( x ^{2} + 4 ) ^{2} ) ( 2 x - 3 )}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

\frac{d}{d x} (2 x - 3) = 2

\frac{d}{d x} ((x^{2} + 4)^{2}) = 4 x (x^{2} + 4)

= \frac{2 ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) ( 2 x - 3 )}{( ( x ^{2} + 4 ) ^{2} ) ^{2}}

Simplify

\frac{2 ( x ^{2} + 4 ) ^{2} - 4 x ( x ^{2} + 4 ) ( 2 x - 3 )}{( ( x ^{2} + 4 ) ^{2} ) ^{2}} : \frac{2 ( - 3 x ^{2} + 6 x + 4 )}{( x ^{2} + 4 ) ^{3}}

= \frac{2 ( - 3 x ^{2} + 6 x + 4 )}{( x ^{2} + 4 ) ^{3}}

\frac{d}{d x} (- x^{2} + 4 x + 1)

\int \frac{( 4 x ^{2} + 4 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

\frac{d}{d x} ((3 + 2 x) e^{- 3 x})

9 y^{^{''}} - 12 y^{^{'}} + 4 y = 0

\frac{5 x ^{2}}{( 3 - 4 x ) ^{4}}

What is the derivative of (2x-3/((x^2+4)^2)) ?
The derivative of (2x-3/((x^2+4)^2)) is (2(-3x^2+6x+4))/((x^2+4)^3)
What is the first derivative of (2x-3/((x^2+4)^2)) ?
The first derivative of (2x-3/((x^2+4)^2)) is (2(-3x^2+6x+4))/((x^2+4)^3)