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Popular >

f(x)=ln(1+sin(4/(x^2)))

Solution

f (x) = ln (1 + sin (\frac{4}{x ^{2}}))

Solution

Parity : Even

Inverse : \frac{2 arcsin ( e ^{x} - 1 )}{arcsin ( e ^{x} - 1 )}, - \frac{2 arcsin ( e ^{x} - 1 )}{arcsin ( e ^{x} - 1 )}

Solution steps

Parity of

ln (1 + sin (\frac{4}{x ^{2}})) :

Even

Inverse of

ln (1 + sin (\frac{4}{x ^{2}})) : \frac{2 arcsin ( e ^{x} - 1 )}{arcsin ( e ^{x} - 1 )}, - \frac{2 arcsin ( e ^{x} - 1 )}{arcsin ( e ^{x} - 1 )}

Popular Examples

tangent of y=sin(4x)+sin^2(4x),(0,0)tangent of

y = sin (4 x) + sin^{2} (4 x), (0, 0)

3 y d x + 2 x d y = 0

integral from 0 to infinity of e^{-4x}

\int_{0}^{\infty} e^{- 4 x} d x

f (x) = 2 x e^{2 x}

integral of (32x^2)/((x-21)(x+7)^2)

\int \frac{32 x ^{2}}{( x - 21 ) ( x + 7 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the f(x)=ln(1+sin(4/(x^2))) ?
The f(x)=ln(1+sin(4/(x^2))) is